思路:递归
// @Title: 合并两个有序链表 (Merge Two Sorted Lists)
// @Author: qisiii
// @Date: 2022-03-10 22:24:18
// @Runtime: 0 ms
// @Memory: 40.7 MB
// @comment: 递归
// @flag: BLUE
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode list1, ListNode list2) {
if(list1==null){
return list2;
}
if(list2==null){
return list1;
}
ListNode result;
if(list1.val<list2.val){
result=list1;
result.next=mergeTwoLists(list1.next,list2);
}else{
result=list2;
result.next=mergeTwoLists(list1,list2.next);
}
return result;
}
}
+++ title = “合并两个有序链表 (Merge Two Sorted Lists)” draft = false +++
思路:
// @Title: 合并两个有序链表 (Merge Two Sorted Lists)
// @Author: qisiii
// @Date: 2024-04-12 23:57:16
// @Runtime: 0 ms
// @Memory: 41.6 MB
// @comment:
// @flag:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode list1, ListNode list2) {
ListNode result=new ListNode(-1),ans=result;
while(list1!=null&&list2!=null){
if(list1.val<list2.val){
ans.next=new ListNode(list1.val);
ans=ans.next;
list1=list1.next;
}else{
ans.next=new ListNode(list2.val);
ans=ans.next;
list2=list2.next;
}
}
if(list1==null){
ans.next=list2;
}else{
ans.next=list1;
}
return result.next;
}
}