思路:
// @Title: 二叉搜索树中的众数 (Find Mode in Binary Search Tree)
// @Author: qisiii
// @Date: 2024-09-16 16:19:59
// @Runtime: 0 ms
// @Memory: 43.9 MB
// @comment:
// @flag:
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
int cur , count = 0, max = 0;
List<Integer> result = new ArrayList<>();
public int[] findMode(TreeNode root) {
dfs(root);
int[] arr = new int[result.size()];
for (int i = 0; i < result.size(); i++) {
arr[i] = result.get(i);
}
return arr;
}
private void dfs(TreeNode root) {
if (root == null) {
return;
}
dfs(root.left);
if (root.val==cur) {
count++;
}else {
cur = root.val;
count = 1;
}
if (count == max) {
result.add(cur);
} else if (count > max) {
max = count;
result.clear();
result.add(cur);
}
dfs(root.right);
}
}